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tanx=3 求3分之2sin平方加4分之一cos平方X的值

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tanx=sinx/cosx=3
sinx=3cosx
sin^2x+cos^2x=1
9cos^2x+cos^2x=1
cos^2x=1/10
2/3(sin^2x)+(cos^2x)/4
=2/3*9cos^2x+(cos^2x)/4
=25/4 cos^2x
=25/4*1/10
=5/8

1年前

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