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已知函数f(x)=x³-3ax²+3x+1 ⑴设a=2求f(x)的单调区间 ⑵设f(x)在区间(2,

已知函数f(x)=x³-3ax²+3x+1 ⑴设a=2求f(x)的单调区间 ⑵设f(x)在区间(2,3)中至少有一个极
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fuzi1234 1年前 悬赏50滴雨露 已收到1个回答 我来回答 举报

room1003 幼苗

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1) f'(x)=3x^2-6ax+3=3(x^2-4x+1)=0,x=2+√5,2-√5
x>=2+√5 or x

1年前

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